Java Program to check Leap Year
Here we will write a java program to check whether
the input year is a leap year or not. Before we see the program, lets see how
to determine whether a year is a leap year mathematically:
To determine whether a year is a leap year, follow
these steps:
1.
If the year is evenly divisible by 4, go to
step 2. Otherwise, go to step 5.
2.
If the year is evenly divisible by 100, go to
step 3. Otherwise, go to step 4.
3.
If the year is evenly divisible by 400, go to
step 4. Otherwise, go to step 5.
4.
The year is a leap year (it has 366 days).
5.
The year is not a leap year (it has 365
days). Source of these steps.
Example: Program to check
whether the input year is leap or not
Here we are using Scanner class to get the input
from user and then we are using if-else statements to write the logic to check
leap year. To understand this program, you should have the knowledge of
following concepts of Core Java Tutorial:
Program Code
package com.androidpro.in;
import java.util.Scanner;
public class Main {
public static void main(String[] args)
{
int year;
Scanner scan = new Scanner(System.in);
System.out.println("Enter any
Year:");
year =
scan.nextInt();
scan.close();
boolean isLeap = false;
if(year % 4 == 0)
{
if( year % 100 == 0)
{
if ( year % 400 == 0)
isLeap = true;
else
isLeap = false;
}
else
isLeap = true;
}
else {
isLeap = false;
}
if(isLeap==true)
System.out.println(year + " is a Leap
Year.");
else
System.out.println(year + " is not a
Leap Year.");
}
}
Output
Enter any Year: 2001 2001 is not a Leap Year. Enter any Year: 1996 1996 is a Leap Year. Process finished with exit code 0
